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https://github.com/simonw/sqlite-utils/issues/117#issuecomment-648440525 https://api.github.com/repos/simonw/sqlite-utils/issues/117 648440525 MDEyOklzc3VlQ29tbWVudDY0ODQ0MDUyNQ== 9599 2020-06-23T21:35:01Z 2020-06-23T21:35:01Z OWNER Here's what's missing: ``` In [11]: db.conn.execute('PRAGMA foreign_key_list(song)').fetchall() Out[11]: [(0, 0, 'album', 'songartist', 'albumartist', 'NO ACTION', 'NO ACTION', 'NONE'), (0, 1, 'album', 'songalbum', 'albumname', 'NO ACTION', 'NO ACTION', 'NONE')] ``` Compare with this code here: https://github.com/simonw/sqlite-utils/blob/d0cdaaaf00249230e847be3a3b393ee2689fbfe4/sqlite_utils/db.py#L563-L579 The first two columns returned by `PRAGMA foreign_key_list(table)` are `id` and `seq` - these show when two foreign key records are part of the same compound foreign key. `sqlite-utils` entirely ignores those at the moment. {"total_count": 0, "+1": 0, "-1": 0, "laugh": 0, "hooray": 0, "confused": 0, "heart": 0, "rocket": 0, "eyes": 0} 644161221  
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